Answer:
Step-by-step explanation:
a) Instead of taking independent samples of mothers and asking them first sample about the weight of their first baby and the second sample about the weight of their second baby this method is better. Because in the first type we do not know whether the mothers have two children and whether they remember weights etc. But in this the difference is ready made got form the eligible mothers
b) Parameter for interest is the difference in weights of two babies
mu1-mu2 where mu1 average weight of I baby while mu2 that of second
c) mu_d = 5oz. where mu_d represents the average difference in weight.
s_d std dev for difference = 7oz
d) Since sample size is >30, we can use Z critical value for confidence interval
Confidence interval = Mean ±1.645*std error
=[tex]5[/tex]±[tex]1.645*\frac{7}{\sqrt{40} }[/tex]
=(3.179, 6.821)
e) In number line the region between 3.179 and 6.821
Yes because if 0 is in the interval we can say there will not be difference. But 0 is not within this interval so would conclude that the mean birth weights for the population are likely to differ