Question

A wooden block of mass= 0.80kg is pulled along a rough horizontal surface with a force of 20N, the block experiences an acceleration of 5ms^-2. what is the magnitude of the frictional force?

Answer 1

The answer is 200 I am sure

Answer 2

Answer:

$F_{r} = 16 \ \rm N$.

Explanation:

Given data:

Mass of the wooden block, $m = 0.80 \ kg$

Applied force, $F = 20 \ \rm N$

Acceleration, $a = 5 \ m/s^{2}$

Let the magnitude of the frictional force be $F_{r}.$

On applying Newton's second law of motion,

$ma = F- F_{r}$

$0.80 \times 5 = 20 - F_{r}$

$\Rightarrow \ F_{r} = 16 \ \rm N.$