Answer:
The volume of the gas at 716 mmHg comes out to be 40.43 mL. This problem is solved by using below equation.
[tex]\textrm{P}\textrm{V} = \textrm{P'}\textrm{V'}[/tex] at constant temperature
Explanation:
Initial volume of gas = V = 37.5 mL
Initial pressure of gas = P = 772 mmHg
Final pressure of gas = P' = 716 mmHg
Assuming final volume of the gas to be V' mL.
[tex]\textrm{P}\textrm{V} = \textrm{P'}\textrm{V'}[/tex] at constant temperature
[tex]\textrm{P}\textrm{V} = \textrm{P'}\textrm{V'} \\772 \textrm{ mmHg} \times 37.5 \textrm{ mL} = 716 \textrm{ mmHg} \times V' \\\textrm{V}' = 40.43 \textrm{ mL }[/tex]
Hence, volume of oxygen gas at 716 mmHg is 40.43 mL.