Question

A jet is circling an airport control tower at a distance of 20.6 km. An observer in the tower watches the jet cross in front of the moon. As seen from the tower, the moon subtends an angle of 9.26x10-3 radians. Find the distance traveled (in meters) by the jet as the observer watches the nose of the jet cross from one side of the moon to the other.

Answer 1

Answer:

197.76 m

Explanation:

r = Radius of the path = 20.6 km = $20.6\times 10^3\ m$

$\theta$ = The angle subtended by moon = $9.6\times 10^{-3}\ rad$

Distance traveled is given by

$s=r\times\theta$

$\Rightarrow s=20.6\times 10^3\times 9.6\times 10^{-3}$

$\Rightarrow s=197.76\ m$

The distance traveled by the jet is 197.76 m

Answer 2

The distance traveled by the jet as the observer watches the nose of the jet cross from one side of the moon to the other is 190.76 m.

The given parameters;

• radius of the circular path, r = 20.6 km
• angle of the observer, θ =  9.26 x 10⁻³ radians

The distance traveled by the jet as the observer watches the nose of the jet cross from one side of the moon to the other is calculated as follows;

$s = \theta \times r\\\\s = 9.26 \times 10^{-3} \times 20600\\\\s = 190.76 \ m$

Thus, the distance traveled by the jet as the observer watches the nose of the jet cross from one side of the moon to the other is 190.76 m.

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