Answer:
22.5 m/s
Explanation:
Applying Newton's third law of motion
Momentum of the cannon and cart = momentum of the cannonball
MV = mv..................... Equation 1
Where M = mass of the cannon and the cart, V = Recoil velocity of the cannon and the cart, m = mass of the cannonball, v = velocity of the cannonball
make v the subject of the equation
v = MV/m............. Equation 2
Given: M = 150 kg, V = 1.5 m/s, m = 10 kg
Substitute into equation 2
v = 150(1.5)/10
v = 22.5 m/s
Hence the cannonball leave the cannon with a velocity of 22.5 m/s
Answer:
v2 = 22.5 m/s
Explanation:
Momentum is how hard to stop or turn a moving object . Generally, momentum measures mass in motion. Momentum is a vector quantity. Mathematically,
p = mass × velocity
The total momentum of an isolated system of bodies remains constant.
mometum before = 0
mass of the canon (m1) = 150 kg
mass of the ball (m2) = 10 kg
velocity of the ball (v2) = ?
velocity of the cannon(v1) = 1.5 m/s
momentum after = momentum before
m2v2 + m1v1 = 0
10v2 = 150 × 1.5
10v2 = 225
divide both sides by 10
v2 = 225/10
v2 = 22.5 m/s
