Question

Bill Board is trying to reduce his sodium intake to an average of 2300 mg.
He records his sodium intake for 4 days.
The amounts are 2150 mg, 3005 mg, 2700 mg, and 2315 mg.
What is the patient’s average daily intake of sodium for those 4 days?
What would his 5th day sodium intake need to be to drop him below an average of 2300 mg

Answer 1

Answer:

mean average = 2542.5 mg

1330 mg

Explanation:

The patient's average  daily intake  of sodium for those 4 days can be calculated by taking the mean average of the sample amounts given over the number of the total days.

$mean average = \frac{2150+3005+2700+2315}{4}$

$mean average = \frac{10170}{4}$

mean average = 2542.5 mg

Therefore the patient's average daily intake of sodium for those 4 days = 2542.5 mg

What is the patient’s average daily intake of sodium for those 4 days?

What would his 5th day sodium intake need to be to drop him below an average of 2300 mg

given that mean average = 2300; we can also determine the fifth day sodium intake as follows:

$mean average = \frac{2150+3005+2700+2315+y}{5}\\2300 = \frac{2150+3005+2700+2315+y}{5}$

$2300*5 =2150+3005+2700+2315+y$

$11500 = 10170 +y$

$11500-10170 =y$

y = 1330 mg

Hence, his sodium intake for the fifth day will be 1330 in order to drop him below an average of 2300 mg