Answer:
The expected amount of pap smears that must be inspected before the first abnormal one is found is 50
Step-by-step explanation:
If 2 percent of all pap smears show signs of abnormality, then the probability that a pap smear is abnormal is 0.02.
Let X be the amount of pap smears needed before the first abnormal case is found. X has geometric ditribution with parameter p = 0.02. The mean of X, in other words, the expected amount of cases that must be inspected before the first abnormal one appears, is 1/p = 1/0.02 = 50.