Respuesta :
Answer:
Option A . 1708 bags
Step-by-step explanation:
The picture of the question in the attached figure
step 1
Find the volume of the silo
The volume of the silo is equal to the volume of a cylinder plus the volume of a cone
so
[tex]V=\pi r^{2}h_1+\frac{1}{3}\pi r^{2}h_2[/tex]
we have
[tex]\pi =3.14[/tex]
[tex]r=16/2=8\ ft[/tex] ---> the radius is half the diameter
[tex]h_1=16\ ft[/tex]
[tex]h_2=12\ ft[/tex]
substitute
[tex]V=(3.14)(8)^{2}(16)+\frac{1}{3}(3.14)(8)^{2}(12)[/tex]
[tex]V=3,215.36+803.84=4,019.2\ ft^3[/tex]
Remember that
The silo is approximately 85% full
so
The volume of grain in the silo is
[tex]0.85(4,019.2)=3,416.32\ ft^3[/tex]
step 2
Find the number of bags of grain
Divide the volume of grain in the silo by the volume of one sack
[tex]3,416.32/2=1,708\ bags[/tex]
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