Question

What is the mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water

Answer 1

Answer:

The mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water is 8.351 %.

Explanation:

Given,

Mass of Sucrose = 7.6 grams

Mass of Water = 83.4 grams

In this solution, Sucrose is solute and water is the solvent.

Mass percent of a solution can be calculated using the formula,

Mass percent =  (Mass of Solute/Mass of Solution)(100)

As sucrose is solute, mass of solute = 7.6 grams

As the solution contains both Sucrose and Water,

Mass of solution = 7.6 grams + 83.4 grams = 91 grams

Substituting the values, Mass percent = (7.6/91)(100) = 8.351 %.

Answer 2

Taking into account the definition of percentage by mass, the mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water is 8.35 %.

The percentage by mass expresses the concentration and is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution and multiplied by 100 to give a percentage. This is:

$percent by mass= \frac{mass of solute}{mass of solution}x100$

In this case, you know:

• mass of solute= 7.6 g
• mass of water= 83.4 g
• mass of solution= mass of solute + mass of water= 7.6 + 83.4 g= 91 g

Replacing:

$percent by mass= \frac{7.6 grams}{91 grams}x100$

Solving:

percent by mass= 0.0835

percent by mass= 8.35 %

Finally, the mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water is 8.35 %.

Learn more:

• brainly.com/question/19168984?referrer=searchResults
• brainly.com/question/18646836?referrer=searchResults