Answer:
The initial current in the circuit is 0.1873 mA
Explanation:
Given;
capacitance is given as 3.67 x 10⁻⁶ F
resistance is given as 8010 Ω
voltage across the circuit is 1.5 V
Since the capacitor is initially uncharged, the capacitive reactance is zero.
From ohms law;
Voltage across the circuit is directly proportional to the opposition to the flow of current.
V = IR
I = V/R
I = 1.5/8010
I = 0.0001873 A = 0.1873 mA
Therefore, the initial current in the circuit is 0.1873 mA