Answer:
[tex]v = 4.2 \ m/s[/tex]
Explanation:
Given data:
Mass of the paper clip, [tex]m = 1.5 \ g = 0.0015 \ kg[/tex]
Kinetic energy, [tex]K = 0.013 \ \rm J[/tex]
Let the velocity of the paper clip when it is thrown be v.
Thus,
[tex]K = \frac{1}{2}mv^{2}[/tex]
[tex]0.013 = 0.5 \times 0.0015 \times v^{2}[/tex]
[tex]\Rightarrow \ v = 4.16 \ m/s[/tex]
[tex]v = 4.2 \ m/s.[/tex] (rounding to nearest tenth)