Question

natural sample of boron consists of two isotopes. One has an exact mass of 10.0129 amu and its percent abundance is 19.91. The other isotope, of mass 11.0093 amu, has a percent abundance of 80.09. Calculate the average atomic mass.

Answer 1

Answer:

10.8109 amu

Step-by-step explanation:

The average atomic mass of boron is determined as the average of the atomic masses of both isotopes weighed by their respective abundances.

Therefore, the average atomic mass is given by:

$M=10.0129*0.1991+11.0093*0.8009\\M=10.8109\ amu$

The average atomic mass of boron isotopes is 10.8109 amu.