A single Na+/K+ ATPase pump is present in the plasma membrane of an artificial cell with an initial cellular environment of 500 molecules of Na+ and 1000 molecules of ATP inside the cell, 500 molecules of K+ outside the cell, and a net charge differential across the plasma membrane of 0. Assuming the only changes in the cellular environment are a result of the pump's actions, what would be the number of Na+, K+ and ATP molecules inside the cell after 10 cycles of the pump and what would be the net charge differential (inside - outside) across the plasma membrane?

a. 300 Na+; 200 K+; 100 ATP and -100 charge differential (inside - outside)
b. 470 Na+; 20 K+; 990 ATP and -20 charge differential (inside - outside)
c. 30 Na+; 20 K+; 900 ATP and -10 charge differential (inside - outside)
d. 470 Na+; 480 K+; 10 ATP and +100 charge differential (inside - outside)
e. 30 Na+; 480 K+; 10 ATP and +20 charge differential (inside - outside)

the correct option is A, because a sodium-potassium pump in a cell requires ONE molecule of ATP for each cycle and exchanges 3 units of sodium for two of potassium, that is why also as the Potassium inside the cell and sodium is excreted in the extracellular medium, the interior value of the cell begins to become negative.

Sodium potassium pumps are fundamental pumps for cellular osmotic balance and are ATP dependent, this means that they need energy to operate.

Histrionicus Histrionicus · Answer 2 · 2021-12-07T15:19:17+01:00

The number of Na⁺ and K⁺ and the net charge differential (inside-outside) across the plasma membrane - (b) 470 Na+; 20 K+; 990 ATP and -20 charge differential (inside-outside)

Given:

Inside the cell

500 molecules - Na⁺

1000 molecules - ATP.

Outside the cell,

500 molecules - K⁺.

Solution:

we know that,

The Na⁺/K⁺ ATPase pump expels 3 molecules of Na+ and enters 2 molecules of K+ with every pump and it costs 1 ATP

Let assume there's only one Na⁺/K⁺ ATPase and there are no other changes in the cellular environment, and the Na⁺/K⁺ ATPase pumps 10 times,

Then,

So, after 10 cycles of pumping,

30 - Na⁺ move out and

20 - K⁺. get in the cell

the cost of - 10 ATP molecules.

Therefore, the net balance of the pumping action:

Inside the cell:

(500-30) sodium ions, (1000-10) ATP and 20 potassium ions

= 470 sodium ions, 990 ATP, 20 potassium. Total charge = 490

Outside the cell:

(500-20) potassium ions, 30 sodium ions

= 480 potassium ions, 30 sodium ions. Total charge = 510

So, charge difference (inside-outside)

= 490-510

= -20

Thus, The number of Na⁺ and K⁺ and the net charge differential (inside-outside) across the plasma membrane - (b) 470 Na+; 20 K+; 990 ATP and -20 charge differential (inside-outside)

Learn more:

https://brainly.com/question/15246547