The gravitational force exerted on a baseball is 2.21 N down. A pitcher throws the ball horizontally with velocity 18.0 m/s by uniformly accelerating it along a straight horizontal line for a time interval of 170 ms. The ball starts from rest. a).- Through what distance does it move before its release? b).- what are the magnitude and direction of the force the pitcher exerts an the ball?.

Respuesta :

Answer:

(a) S = 1.8m

(b) F = 23.9N

Explanation:

The solution to this problem requires the knowledge of the concepts of constant acceleration motion for part (a) and newton's second law for part(b).

(a) s =(u + v)/2 ×t

(b) F = m(v-u)/t

u = 0m/s because the pitcher starts to throw the ball from rest

See attachment below for full solution steps.

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