Answer:
The overall change in the oxidation number of sulfur is 8.
Explanation:
Oxidation number is defined number assigned to an element in reaction which represent the loss or gain of electrons by an atom of an element in a compound.
In [tex]H_2S[/tex]
let the oxidation number of S in hydrogen sulfide be x.
[tex](+1\times 2)+x=0[/tex]
x = -2
In [tex]SO_4^{2-}[/tex]
let the oxidation number of S in sulfate ion be x.
[tex]x+(-2\times 4)=-2[/tex]
x = -2 + 8 = +6
The overall change in the oxidation number of sulfur :
= [+6] - [-2] = 8
[tex]S^{-2}\rightarrow S^{+6}+8e^-[/tex]