Question

nert xenon actually forms many compounds, especially with highly electronegative fluorine. The ΔH o f values for xenon difluoride, tetrafluoride, and hexafluoride are −105, −284, and −402 kJ/mol, respectively. Find the average bond energy of the XebondF bonds in each fluoride.

Answer 1

Answer:

For Xenon fluoride, the average bond energy is 132kj/mol

For tetraflouride,the average bond energy is 150.5kj/mol.

For hexaflouride, the average bond energy is 146.5 kj/mol

Explanation:

For xenon fluoride

105/2 = 52.5

For F-F

159/2 = 79.5

Average bond energy of Xe-F = 79.5 + 52.5 = 132kj/mole

For tetraflouride

284/4 = 71

For F-F

159/2 = 79.5

Average bond energy = 79.5 + 71 = 150.5kj/mol

For hexaflouride

402/6 = 67

F-F = 159/2 = 79.5

Average bond energy = 67 + 79.5 = 146.5kj/ mol

Answer 2

The average bond energy for Xenon difluoride, Xenon tetraflouride, and Xenon hexafluoride is 132kJ/mol,  150.5kJ/mol, and 146.5 kJ/mol respectively

Average Bond Energy:

For xenon difluoride, the average energy is:

105/2 = 52.5 kJ/mole

From the Florine-Florine bond, the average energy for fluorine bond is:

159/2 = 79.5 kJ/mole

Average bond energy of Xe-F = 79.5 + 52.5 = 132 kJ/mole

Similarly, for Xenon tetrafluoride:

the average energy is: 284/4 = 71 kJ/mole

From the Florine-Florine bond, the average energy for fluorine bond is

159/2 = 79.5 kJ/mole

Average bond energy = 79.5 + 71 = 150.5kJ/mol

For Xenon hexafluoride

the average energy is: 402/6 = 67 kJ/mole

From the Florine-Florine bond, the average energy for fluorine bond is: 159/2 = 79.5 kJ/mole

Average bond energy = 67 + 79.5 = 146.5kJ/ mol

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