The sea water has 8.0x10^-1 cg of element strontium. Assuming that all strontium could be recovered, how many grams of strontium could be obtained from 9.84x10^8 cubic meter of seawater. Assuming the density of sea water is 1.0g/mL.

Respuesta :

Answer:

       [tex]\large\boxed{\large\boxed{7.9\times 10^9g}}[/tex]

 

Explanation:

The information of the content of  the element strontium in seawater is incomplete. The complete information is:

  • The seawater has 8.0×10⁻¹cg of element strontium per kilogram of seawater.

Solution

1. First, convert the given volume of seawater given to kilograms

[tex]9.84\times 10^{8} m^3\times \dfrac{1,000dm^3}{m^3}\times \dfrac{1,000cm^3}{dm^3}\times 1.0\dfrac{g}{cm^3}\times\dfrac{1kg}{1,000g}=9.84\times 10^{11}kg[/tex]

2. Second, multiply the given concentration of the element strontium by the amount of seawater in kilograms

     [tex]8.0\times 10^-1cg/kg\times 9.84\times 10^{11}kg\times 1g/100cg=7.872\times 10^9g[/tex]

3. Finally, round to two significant figures:

     [tex]7.9\times 10^9g[/tex]

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