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Light travels through a substance at 1.97 x 10^8 m/s. What is the index of the liquid? What type of liquid is it?

Respuesta :

The refractive index of the liquid is 1.52. The substance is a crown glass.

Explanation:

Given:

Velocity of light through the substance, v = 1.97 X 10⁸ m/s

Refractive index of the liquid, μ = ?

We know,

μ = [tex]\frac{c}{v}[/tex]

where, c = velocity of light in air

            v = velocity of light in the substance

speed of light in air is 3 X 10⁸m/s

[tex]= \frac{3 X 10^8}{1.97 X 10^8} \\\\= 1.52\\[/tex]

Therefore, refractive index of the liquid is 1.52. The substance is a crown glass.

n = 1.52

Index of the liquid = 1.52

The type of the liquid is Crown glass.

Explanation:

In finding the index of refraction, we use this formula

n = c/v

where n is the index of refraction

c is velocity of light in vacuum which is constant and is equivalent to [tex]3 \times 10^{8} \mathrm{m} / \mathrm{s}[/tex]

v is the velocity of light in a particular medium

Here we use [tex]1.97 \times 10^{8} \mathrm{m} / \mathrm{s}[/tex]

Using the formula,

n = c/v

n = [tex]3 \times 10^{8} / 1.97 \times 10^{8}[/tex]

n = 1.52284264

n = 1.52

Thus, the index of the liquid is 1.52

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