Answer:
Explanation:
Given that,
Number of turn is 48
N=48
Radius is 4.8cm
r=0.048m
Magnetic Field
B=0.48T
Current in coil
i=23.3mA
i=0.233A
Maximum Torque?
Maximum torque occur at angle 90°
Torque is given as
τ = N•I•A•B•sinθ
Where N is number of turn =48
I is current in coil =0.233A
A is area of circular coil form
Area of a circle is given as
A=πr²
A=π×0.048²
A=0.007238m²
B is magnetic field =0.48T
Maximum torque occurs at 90°
τ = N•I•A•B•sinθ
τ=48×0.233×0.007238×0.48×Sin90
τ = 0.0389Nm
This torque is large enough to exert the coil
Given Information:
Magnetic field = B = 0.480 T
Current = I = 23.3 mA = 0.0233 A
Number of turns = N = 48 turns
Radius = r = 5.50 cm = 0.055 m
Required Information:
Maximum possible torque = τ = ?
Answer:
Maximum possible torque = 0.0051 N.m
Explanation:
We know that toque τ is given by
τ = NIABsin(θ)
Where N is the number of turns of the circular coil, I is the current flowing through the circular coil, A is the area of circular coil, B is the magnetic field induced in the circular coil.
The area of the circular coil is
A = πr²
A = π(0.055)²
A = 0.009503 m²
The maximum torque is possible when θ = 90°
τ = 48*0.0233*0.009503*0.480*sin(90°)
τ = 0.0051 N.m
