Respuesta :
Answer:
We need at least 217 compact fluorescent light bulbs
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1-0.99}{2} = 0.005[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].
So it is z with a pvalue of [tex]1-0.005 = 0.995[/tex], so [tex]z = 2.575[/tex]
Now, find M as such
[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
How many compact fluorescent light bulbs need to be selected?
We need at least n bulbs, in which n is found when [tex]M = 175, \sigma = 1000[/tex]
So
[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]
[tex]175 = 2.575*\frac{1000}{\sqrt{n}}[/tex]
[tex]175\sqrt{n} = 2575[/tex]
[tex]\sqrt{n} = \frac{2575}{175}[/tex]
[tex]\sqrt{n} = 14.71[/tex]
[tex]\sqrt{n}^{2} = (14.71)^{2}[/tex]
[tex]n = 216.5[/tex]
We need at least 217 compact fluorescent light bulbs
The number of compact fluorescent light bulbs that needs to be selected is 217
The given parameters are:
[tex]\sigma = 1000[/tex] ---- the population standard deviation
[tex]E =\pm 175[/tex] ---- the margin of error
At 99% confidence interval, the z value is 2.576.
So, the margin of error is calculated using:
[tex]E = z \times \frac{\sigma}{\sqrt n}[/tex]
Substitute values for the margin of error (E) and the standard deviation ([tex]\sigma[/tex]).
So, we have:
[tex]\pm 175 = 2.576 \times \frac{1000}{\sqrt n}[/tex]
Multiply both sides by [tex]\frac{\sqrt n}{\pm 175}[/tex]
[tex]\sqrt n= 2.576 \times \frac{1000}{\pm 175 }[/tex]
This gives
[tex]\sqrt n= \frac{2576}{\pm 175 }[/tex]
Divide
[tex]\sqrt n= \pm14.72[/tex]
Square both sides of the equation
[tex]n= 216.6784[/tex]
Approximate
[tex]n= 217[/tex]
Hence, the number of compact fluorescent light bulbs that needs to be selected is 217
Read more about margin of error at:
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