Respuesta :
Answer:
maximum electric strength is 0.016 V/m
Explanation:
given data
Potential V = 4 mV = 4 × [tex]10^{-3}[/tex] V
potential across = 0.250 m
Frequency f = 1 Hz
solution
we get here electric field that is
E = [tex]\frac{V}{d}[/tex] ...................1
put here value and we get
E = [tex]\frac{4\times 10^{-3}}{0.250}[/tex]
E = 0.016 V/m
maximum electric strength is 0.016 V/m
Answer:
Explanation:
Potential difference, V = 4 mV = 0.004 V
distance, d = 0.25 m
The relation between the electric field strength and the potential difference is given by
V = E x d
0.004 = E x 0.25
E = 0.016 V/m
Thus, the maximum value of the electric field is 0.016 V/m.