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Object 1 has a mass m1 and a velocity v1 = (2.50 m/s )x^. Object 2 has a mass m2 and a velocity v2 = (3.00 m/s )y^. The total momentum of these two objects has a magnitude of 20.0 kg⋅m/s and points in a direction 65.0 ∘ above the positive x axis.part a find m1.part b Find m2.

Respuesta :

Answer:

[tex]m_{1} \approx 3.381\,kg[/tex]

[tex]m_{2}\approx 6.042\,kg[/tex]

Explanation:

The equation for momentum are:

x:

[tex]m_{1}\cdot (2.50\,\frac{m}{s}) = 20\,\frac{kg\cdot m}{s}\cdot \cos 65^{\textdegree}[/tex]

y:

[tex]m_{2}\cdot (3\,\frac{m}{s} ) = 20\,\frac{kg\cdot m}{s}\cdot \sin 65^{\textdegree}[/tex]

Masses are, respectively:

[tex]m_{1} \approx 3.381\,kg[/tex]

[tex]m_{2}\approx 6.042\,kg[/tex]

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