Answer:
The speeds of the electrons is [tex]8.79\times10^{7}\ m/s[/tex]
Explanation:
Given that,
Potential difference = 22000 V
The difference in electron potential energy is converted into kinetic energy.
We need to calculate the speed
Using conservation of energy
[tex]K.E=\Delta EPE[/tex]
[tex]\dfrac{1}{2}mv^2=q\Delta V[/tex]
[tex]v=\sqrt{\dfrac{2q\Delta V}{m}}[/tex]
Where, V = potential difference
q = charge of electron
m = mass of electron
[tex]v=\sqrt{\dfrac{2\times1.6\times10^{-19}\times22000}{9.1\times10^{-31}}}[/tex]
[tex]v=8.79\times10^{7}\ m/s[/tex]
Hence, The speeds of the electrons is [tex]8.79\times10^{7}\ m/s[/tex]