Answer:
t = 8.9 10-3 s
Explanation:
The charge on an RL circuit is
I = I₀ (1 - [tex]e^{-t/tau}[/tex])
Where tau is the circuit response time
τ = L / R
i / io = 1- [tex]e_{-t/\tau }[/tex]
0.5 = 1-e_{-t/\tau }
e_{-t/\tau } = 1 /0.5 = 0.5
-t / τ = ln 0.5
t = τ ln 0.5
τ = L / R
t = L / R ln 0.5
t = 1.8 / 1.4 103 ln 0.5
t = 8.9 10-3 s