Answer:
annual withdrawals is $1,393.87
Explanation:
given data
Amount Deposited = $5,000
Annual Interest Rate = 7.2%
First withdrawal = 2020
last withdrawal = 2025
solution
we consider equal sized annual withdrawals = x
so we can say that Amount Deposited amount will be as
$5,000 = [tex]\frac{x}{(1+0.72)^5} + \frac{x}{(1+0.72)^6} + \frac{x}{(1+0.72)^7} + \frac{x}{(1+0.72)^8} + \frac{x}{(1+0.72)^9} + \frac{x}{(1+0.72)^{10}}[/tex] ..........1
we take common here [tex]\frac{x}{(1+0.72)^{4}}[/tex]
so
$5,000 = [tex]\frac{x}{(1+0.72)^{4}} \times ( \frac{1}{(1+0.72)^1} + \frac{1}{(1+0.72)^2} + \frac{1}{(1+0.72)^3} + \frac{1}{(1+0.72)^4} + \frac{1}{(1+0.72)^5} + \frac{1}{(1+0.72)^{6}} )[/tex]
solve it we get
x = $1,393.87
so that annual withdrawals is $1,393.87