The measure of arc EG = 16°.
Solution:
Given data:
m∠X = 47° and m(ar FH = 110°)
To find the measure of arc EG:
We know that,
Angle formed by two intersecting secants outside the circle is equal to half of the difference between the intercepted arcs.
[tex]$m \angle X=\frac{1}{2}({arc} \ FH-{arc} \ EG)[/tex]
[tex]$47^{\circ}=\frac{1}{2}\left(110^\circ- {arc} \ EG}\right)[/tex]
Multiply by 2 on both sides.
94° = 110° - arc EG
Subtract 110° from both sides.
-16° = -arc EG
Multiply -1 on both sides, we get
16° = arc EG
Switch the sides.
arc EG = 16°
The measure of arc EG = 16°.
