Answer:
The amount of heat required comes out to be 190.4 KJ
Explanation:
The reaction for the decomposition of [tex]NaHCO_{3}[/tex] is shown below [tex]\textrm{NaHCO}_{3}\left ( s \right )\rightarrow \textrm{Na}_{2}\textrm{CO}_{3}\left ( s \right )+\textrm{H}_{2}\textrm{O}\left ( l \right )+\textrm{CO}_{2}\left ( g \right )[/tex]
Amount of heat required to decompose 1 mole [tex]NaHCO_{3}[/tex] = 85 KJ
Amount of heat required to decompose 2.24 mole [tex]NaHCO_{3}[/tex] = [tex]\left ( 2.24 \textrm{ mole} \times 85 \textrm{ KJ} \right ) = 190.4 \textrm{ KJ}[/tex]
Amount of heat required = 190.4 KJ