Given the following information: aHCO3(s)+85 kJ Na2CO3(s)+H2O(1) CO2(g) Calculate the amount of heat (ink) required to decompose 2.24 mol NaHCO3(s). You must show your work to receive credit .

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Answer:

The amount of heat required comes out to be 190.4 KJ

Explanation:

The reaction for the decomposition of [tex]NaHCO_{3}[/tex] is shown below [tex]\textrm{NaHCO}_{3}\left ( s \right )\rightarrow \textrm{Na}_{2}\textrm{CO}_{3}\left ( s \right )+\textrm{H}_{2}\textrm{O}\left ( l \right )+\textrm{CO}_{2}\left ( g \right )[/tex]

Amount of heat required to decompose 1 mole [tex]NaHCO_{3}[/tex]  = 85 KJ

Amount of heat required to decompose 2.24 mole [tex]NaHCO_{3}[/tex] = [tex]\left ( 2.24 \textrm{ mole} \times 85 \textrm{ KJ} \right ) = 190.4 \textrm{ KJ}[/tex]

Amount of heat required = 190.4 KJ

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