Answer:
The molecular formula of the compound is [tex]C_{8}H_{16}O_{4}[/tex].
Explanation:
Given empirical formula of the compound is [tex]C_{2}H_{4}O[/tex].
Atomic mass of carbon = 12 u
Atomic mass of hydrogen = 1 u
Atomic mass of oxygen = 16 u
Empirical formula mass of compound = [tex]\left ( 12\times 2+4+16 \right ) = 44 \textrm{ g/mol}[/tex]
Molecular mass of compound = 176 g/mol
[tex]n = \displaystyle \frac{176}{44} = 4[/tex]
Molecular formula = n [tex]\times[/tex] Empirical formula
Molecular formula = 4 [tex]\times[/tex] [tex]C_{2}H_{4}O[/tex]
Molecular formula of the compound is [tex]C_{8}H_{16}O_{4}[/tex]
