Question

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 84.5 cm and diameter 2.40 cm from a storage room to a machinist. Calculate the weight of the rod, w. Assume the free-fall acceleration is g = 9.80 m/s2 .

Answer 1

Answer:

29.22 N

Explanation:

Parameters given:

Density = 7800 kg/m³

Diameter of rod = 2.4cm = 0.024m

Radius = 0.012m

Length = 84.5cm = 0.845m

To find the weight, we must find get the mass.

Density is given as:

Density = mass/volume

Therefore, mass is:

Mass = density * volume

Volume of the cylindrical rod is:

Volume = pi * r² * h

Volume = 3.142 * 0.012² * 0.845

Volume = 0.0003823 m³

Mass = 7800 * 0.0003823

Mass = 2.982 kg

Weight = m * g

Where g is acceleration due to gravity

Weight = 2.982 * 9.8 = 29.22 N