An object falls 210 m in 6.3 s. What was it's initial velocity? Express your answer with the correct number of significant digits.

Respuesta :

Answer:

[tex]u = 2.5 \ m/s[/tex]

Explanation:

Given data:

Height, [tex]h = 210 \ m[/tex]

Time, [tex]t = 6.3 \ s[/tex]

Let the initial velocity of the object be u.

From the kinematic equation,

[tex]h = ut + \frac{1}{2}gt^{2}[/tex]

[tex]210 = u \times 6.3 + 0.5 \times 9.80 \times (6.3)^{2}[/tex]

[tex]\Rightarrow \ u = 2.46 \ m/s[/tex]

[tex]u = 2.5 \ m/s[/tex] (rounding to tenth place)