Answer:
3,159 bytes
Explanation:
When implemented as a macro, for each of the 35 executions, the program will require enough memory for the whole macro code (61 bytes). Since the program's data and executable code require 1,024 bytes, the number of bytes required by the entire program is:
[tex]M = 1,024+(35*61)\\M=3,159\ bytes[/tex]
The program requires 3,159 bytes if the new code is added as a macro.