Question

16. The presence of freckles (F) is dominant to the absence of freckles (f). Using Punnett squares, determine the phenotypic and genotypic ratios that you would expect from the following crosses: a. Parent 1: Homozygous dominant Parent 2: Homozygous recessive b. Parent 1: Heterozygous Parent 2: Homozygous recessive c. Parent 1: Homozygous recessive Parent 2: Homozygous recessive d. Parent 1: Heterozygous Parent 2: Heterozygous

Answer 1

Answer:

There is no short answer.

Explanation:

The genotypes for the two parents in option A are FF and ff, so the resulting phenotypic and genotypic ratios that would be 100% absence of freckles and 100% Ff respectively.

The genotypes for the two parents in option B are Ff and ff, so the resulting phenotypic and genotypic ratios that would be 100% absence of freckles and 50% Ff, 50% ff respectively.

The genotypes for the two parents in option C are ff and ff, so the resulting phenotypic and genotypic ratios that would be 100% absence of freckles and 100% ff respectively.

The genotypes for the two parents in option D are Ff and Ff, so the resulting phenotypic and genotypic ratios that would be 75% absence of freckles, 25% freckles and 50% Ff, 25% FF, 25% ff respectively.

I hope this answer helps.