Answer:
4.48%
Step-by-step explanation:
The first thing is to take into account all the possible events as follows
If D is disease present
If ND is disease not present
If P is a positive test
If F is test false
From the statement we have the following information:
P (D) = 0.05% = 0.005
P (P | D) = 99% = 0.99
P (P | ND) = 4% = 0.04
The total number of% positive tests would be the sum of the positive tests when the disease is% present and the positive tests when the disease is not present that it false positives.
Therefore the equation would be like this:
P (P) = P (P | D) * P (D) + P (P | ND) * (1 - P (D))
Replacing the values:
P (P) = 0.99 * 0.005 + 0.04 * (1 - 0.005)
P (P) = 0.00495 + 0.0398
P (P) = 0.04475
What it means is that the probability that they are positive is 4.48%