To solve this problem we will apply the concepts related to the electromagnetic force given between two cables. For this purpose we will consider the following mathematical relation,
[tex]F = \frac{\mu_0I_1I_2L}{(2\pi d)}[/tex]
Here,
[tex]\mu_0[/tex] = Permeability at free space
[tex]I_{1,2}[/tex] = Current
L = Length
d = Distance between them
With our values we have,
[tex]F = \frac{(4\pi*10^{-7}) (140)(140) (254)}{(2\pi (40*10^{-2}))}[/tex]
[tex]F = 2.4892N[/tex]
Therefore the force between the wires is 2.4892 N as the current flows in oposite direction, the force is away from each other.