Answer:
=[TeX]\frac{5}{13}[/TeX]
Step-by-step explanation:
Total Number of Cards=52
Number of Cards having a point value of 10=16
Number of Aces=4
We want to determine the probability that both cards dealt are aces or 10-point cards.
P(Aces) = [TeX]\frac{4}{52}[/TeX]
P(10 point cards)=[TeX]\frac{16}{52}[/TeX]
Definition
If A and B are mutually exclusive events,
Probability (A OR B) = P(A)+P(B)
P(both cards dealt are aces or 10-point cards) = P(Aces) + P(10 point cards)
=[TeX]\frac{4}{52}+\frac{16}{52}[/TeX]
=[TeX]\frac{20}{52}= \frac{5}{13}[/TeX]