Answer:
[tex]T_F=31.9^0C[/tex]
Explanation:
Hello,
In this case, the energy content is modeled via:
[tex]Q=mCp(T_F-T_0)[/tex]
Since the unknown is the final temperature, it is solved by:
[tex]T_F=T_0+\frac{Q}{mCp} =33.9^0C+\frac{-69.0kJ}{8.10kg*4.18\frac{kJ}{kg*^0C}} \\T_F=31.9^0C[/tex]
The heat is negative since it flows out of the bath that is the considered system.
Best regards.