Question

Velvetleaf is a particularly annoying weed in cornfields. It produces lots of seeds, and the seeds wait in the soil for years until conditions are right. How many seeds do velvetleaf plants produce? (Use 96% confidence). Here are counts from 28 plants that came up in a cornfield when no herbicide was used:

2450 2504 2114 1110 2137 8015 1623 1531 2008 1716721 863 1136 2819 1911 2101 1051 218 1711 1642228 363 5973 1050 1961 1809 130 880

Answer 1

Answer:

96% CI for the production of seeds

$1177.5\leq\mu\leq2520.5$

Step-by-step explanation:

We have a sample of size n=28. With these data we can calculate the mean and standard deviation of the sample.

Sample = [2450, 2504, 2114, 1110, 2137, 8015, 1623, 1531, 2008, 1716, 721, 863, 1136, 2819, 1911, 2101, 1051, 218, 1711, 1642, 228, 363, 5973, 1050, 1961, 1809, 130, 880 ]

Sample mean = 1849

Sample standard deviation = 1647

To calculate a 96% confidence interval, we use the t-statistic with df=27.

The t-value for this condition is t=2.1578.

$M\pm t_{27}*s/\sqrt{n}\\\\1849\pm2.1578*1647/\sqrt{28}\\\\1849\pm671.5\\\\\\1849-671.5\leq\mu\leq 1849+671.5\\\\\\1177.5\leq\mu\leq2520.5$

Then, the 96% interval is

$1177.5\leq\mu\leq2520.5$

Answer 2

The 96% interval is [117.5,2520.5] and this can be determined by using the t-statistics and the given data.

Given :

• Sample Size = 28
• Sample = [2450, 2504, 2114, 1110, 2137, 8015, 1623, 1531, 2008, 1716, 721, 863, 1136, 2819, 1911, 2101, 1051, 218, 1711, 1642, 228, 363, 5973, 1050, 1961, 1809, 130, 880]

The sample mean for this is 1849 and the standard deviation is 1647.

Use t-statistic with df = 27 to calculate 96% confidence interval. So, the t-value is 2.1578.

$\rm M\pm t_{27}\times \dfrac{s}{\sqrt{n} }$

$1849\pm 2.1578 \times \dfrac{1647}{\sqrt{28} }$

$1849\pm 671.5$

$1849-671.5\leq \mu \leq 1849+671.5$

$117.5\leq \mu \leq 2520.5$

Therefore, the 96% interval is [117.5,2520.5].

For more information, refer to the link given below:

https://brainly.com/question/23044118