Question

4a.) A 0.50 kg water balloon is thrown against a wall at 32 m/s coming to a stop. What was its change in
momentum?

Answer 1

Answer:

-16 kg m/s

Explanation:

Momentum is a vector quantity indicating the "amount of motion" in an object.

The change in momentum of an object is given by:

$\Delta p = m(v-u)$

where:

m is the mass of the object

u is its initial velocity

v is its final velocity

For the water balloon in this problem, we have:

m = 0.50 kg is the mass

u = 32 m/s is the initial velocity

v = 0 m/s (since the balloon comes to a stop)

Therefore, the change in momentum is:

$\Delta p=(0.50)(0-32)=-16 kg m/s$

And the negative sign indicates that the direction is opposite to the initial velocity.