Question

Near San Francisco, where the vertically downward component of the earth's magnetic field is 4.0 x 10-5 T, a car is traveling forward at 26 m/s. The width of the car is 1.9 m. Find the emf induced between the two sides of the car. If positive charge accumulates on the driver's side, the enter the emf as a positive number. If negative charge accumulates on the driver's side, the enter the emf as a negative number.

Answer 1

Answer:

Induced emf will be equal to $1.97\times 10^{-3}volt$

Explanation:

We have given magnetic field $B=4\times 10^{-5}T$

A car is travelling with a speed of 26 m/sec

So velocity of the car v = 26 m/sec

Width of the car l = 1.9 m

We know that emf is equal to

$E=Bvl$

So $E=4\times 10^{-5}\times 26\times 1.9=197\times 10^{-5}volt =1.97\times 10^{-3}volt$

So induced emf will be equal to $1.97\times 10^{-3}volt$

Answer 2

Answer:

Explanation:

Magnetic field, B = 4 x 10^-5 T

velocity, v = 26 m/s

length, l = 1.9 m

the formula for the induced emf is given by

e = B x v x l

e = 4 x 10^-5 x 26 x 1.9

e = 1.976 x 10^-3 v

e = 1.976 mV