The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)Year Population1750 7901800 9801850 12601900 16501950 25602000 6080A) Use the exponential model and the population figures for 1750 and 1800 to predict the world population in 1950. B) Use the exponential model and the population figures for 1850 and 1900 to predict the world population in 1950.C) Use the exponential model and the population figures for 1900 and 1950 to predict the world population in 2000.

Respuesta :

Answer:

(a)1867 (b)2162 (c)3978

Step-by-step explanation:

The exponential population model is given as:

[TeX]P(t)=P_{0}e^{rt}[/TeX]

where [TeX]P_{0}[/TeX] is the initial population for the given time period.

A)

In 1750, population was 790

In 1800, population was 980

P(50)=980

P(0)=790

Using our model

[TeX]P(t)=P_{0}e^{rt}[/TeX]

[TeX]980=790e^{rX50}[/TeX]

[TeX]\frac{980}{790}=e^{rX50}[/TeX]

[TeX]1.2405=e^{rX50}[/TeX]

Taking natural logarithm of both sides

ln 1.2405 = 50r

r= ln 1.2405÷50=0.0043

Our model is then:

[TeX]P(t)=790e^{0.0043t}[/TeX]

In 1950, 200 years after

t=200

[TeX]P(t)=790e^{0.0043X200}[/TeX]

=1866.9

P(t)=1,867 million

(b)In 1850, population was 1260

In 1900, population was 1650

P(50)=1650

P(0)=1260

Using our model

[TeX]P(t)=P_{0}e^{rt}[/TeX]

[TeX]1650=1260e^{rX50}[/TeX]

[TeX]\frac{1650}{1260}=e^{rX50}[/TeX]

[TeX]1.3095=e^{rX50}[/TeX]

Taking natural logarithm of both sides

ln 1.3095 = 50r

r= ln 1.3095÷50=0.0054

Our model is then:

[TeX]P(t)=1260e^{0.0054t}[/TeX]

In 1950, 100 years after

t=100

[TeX]P(t)=1260e^{0.0054X100}[/TeX]

=2162.17

P(t)=2,162 million

(c)In 1900, population was 1650

In 1950, population was 2560

P(50)=2560

P(0)=1650

Using our model

[TeX]P(t)=P_{0}e^{rt}[/TeX]

[TeX]2560=1650e^{rX50}[/TeX]

[TeX]\frac{2560}{1650}=e^{rX50}[/TeX]

[TeX]1.5515=e^{rX50}[/TeX]

Taking natural logarithm of both sides

ln 1.5515 = 50r

r= ln 1.5515÷50=0.0088

Our model is then:

[TeX]P(t)=1650e^{0.0088t}[/TeX]

In 2000, 100 years after

t=100

[TeX]P(t)=1650e^{0.0088X100}[/TeX]

=3977.98

P(t)=3978 million

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