Respuesta :
Answer:
Energy stored at 12 volt will be 115.2 J and energy stored at 24 volt will be 460.8 volt
Explanation:
We have given capacitance of capacitor C = 1.6 F
Normal voltage V = 12 volt
And system uses 2 volt to charge the system
We know that energy stored in the capacitor is equal to [tex]E=\frac{1}{2}CV^2[/tex]
So energy stored at 12 volt will be equal to [tex]E=\frac{1}{2}\times 1.6\times 12^2=115.2j[/tex]
And energy stored at 24 volt will be equal to [tex]E=\frac{1}{2}\times 1.6\times 24^2=460.8j[/tex]
So energy stored at 12 volt will be 115.2 j and energy stored at 24 volt will be 460.8 j
Answer:
Explanation:
Capacitance, C = 1.6 F
(a) V = 12 V
Energy stored in a capacitor,
U = 0.5 C V²
U = 0.5 x 1.6 x 12 x 12 = 115.2 J
(b) V = 24 V
Energy stored in a capacitor,
U = 0.5 C V²
U = 0.5 x 1.6 x 24 x 24 = 460.8 J