Question

How many moles are in 431 g of Cesium nitrate, CsNO3?

1 point

Your answer


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Answer 1

Answer: n = 2.21 moles CsNO3

Explanation: To solve for the moles of CsNO3 we will convert the mass of CsNO3 to moles by dividing it to its molar mass.

431 g CsNO3 x 1 mole CsNO3 / 195 g CsNO3

= 2.21 moles CsNO3

Answer 2

Answer:

The number of moles in Cesium Nitrate, CsNO3 is 2.2112 moles

Explanation:

Moles of a substance n, is given by the mass, m of the substance divided by the molar mass, mm of the substance.

${Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of $CsNO_{3}$ = a(Cs) + a(N) + a(O3)

where a is the atomic mass;

a(Cs)=132.91 a(N)=14 a(O)=16

Therefore, Mm(CsNO3) = [132.91] + [14] + [16*3]

Mm(CsNO3) = 132.91+14+48

Mm(CsNO3) = 194.91

${Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

${Number of moles}=\frac{431}{194.91}$

Number of moles = 2.2112moles

Hence, the number of moles in 431g of Cesium Nitrate is 2.2112moles