Question

O points
A bottle of drinking water fills plastic bottles with a mean volume of 998
mL and standard deviation of 7 mL. The fill volumes are normally
distributed. What proportion of bottles have volumes greater than 999
mL?

Answer 1

7.5 %

Step-by-step explanation:

We by finding how far from the mean the 999 volume caps are, using z score;

Z = (x – μ) / σ

Z = (999 – 998) / 7

Z = 0.143    

We use the z-table to find the confidence levels;

= 85%

= 0.85

Since we are finding proportion of bottles have volumes greater than 999

mL;

1 – .85 = .15

0.15/2 = 0.075

= 7.5%