Respuesta :
Answer:
(a) The mean score of test A is 1210.
(b) The mean score of test A is 1210.
(c) The standard deviation of test A is 80.
(d) The value of Q₃ for test A is 1170.
(e) The value of median for test A is 1090.
(f) The value of IQR for test A is 290.
Step-by-step explanation:
The relation between two standardized tests A and B is:
[tex]50A=40B+50[/tex]
The equation above approximates the relationship between scores on the two tests.
The summary statistics for test B are as follows:
Lowest Score = 21
Mean score = 29
Standard deviation = 2
Q₃ = 28
Median = 26
IQR = 6
(a)
Compute the lowest score on test A as follows:
[tex]A=40B+50\\=(40\times21)+50\\=890[/tex]
Thus, the lowest score on test A is 890.
(b)
Compute the mean score of test A as follows:
[tex]A=40B+50\\=(40\times29)+50\\=1210[/tex]
Thus, the mean score of test A is 1210.
(c)
Compute the mean score standard deviation of test A as follows:
[tex]A=40B+50\\=(40\times2)\\=80[/tex]
Thus, the standard deviation of test A is 80.
(d)
Compute the value of Q₃ for test A as follows:
[tex]A=40B+50\\=(40\times28)+50\\=1170[/tex]
Thus, the value of Q₃ for test A is 1170.
(e)
Compute the value of median for test A as follows:
[tex]A=40B+50\\=(40\times26)+50\\=1090[/tex]
Thus, the value of median for test A is 1090.
(f)
Compute the value of IQR for test A as follows:
[tex]A=40B+50\\=(40\times6)+50\\=290[/tex]
Thus, the value of IQR for test A is 290.