Question

A baseball approaches home plate at a speed of 45.0 m/s, moving horizontally just before being hit by a bat. The batter hits a pop-up such that after hitting the bat, the baseball is moving at 55.0 m/s straight up. The ball has a mass of 145 g and is in contact with the bat for 2.00 ms. What is the average vector force the ball exerts on the bat during their interaction?

Answer 1

Answer:

Average force vectors is 3987.5j - 3262.5i

Explanation:

Given :

Initial speed of baseball, u = 45 m/s

Final speed of baseball. v = 55 m/s

Mass of baseball, m = 145 g = 0.145 kg

Contact time between baseball and bat, t = 2 ms = 2 x 10⁻³ s

Consider the initial direction of baseball be positive along horizontal and after hitting the bat, the direction of baseball be positive along vertical direction.

Applying Newton's Second law, the average force vector is given by the relation:

$F=m\frac{(v-u)}{t}$

Substitute the suitable values in the above equation.

$F=0.145\times\frac{(55j-45i)}{2\times10^{-3} }$

F = 3987.5j - 3262.5i