Question

If 16g of $CH_{4}$ reacts with 64g of $O_{2}$ to produce 36g of $H_{2}O$, how many grams of $CO_{2}$ are produced?

Answer 1

43.56 grams of  are produced if 16g of  CH4 reacts with 64g of O2.

Explanation:

Balance equation for the reaction:

CH4 + 2O2⇒ CO2 +2H2O

Data given : mass of CH4 =16 grams  atomic mass = 16.04 grams/mole

                    mass of water 36 gram  atomic mass = 18 grams/moles

                   mass of CO2=?                atomic mass = 44.01 grams/mole

number of moles = $\frac{mass}{atomic mass of one mole}$    equation 1

number of moles in CH4

   n = $\frac{16}{16.04}$

       = 0.99 moles

Since combustion is done in presence of oxygen hence it is an excess reagent and methane is limiting reagent so production of CO2 depends on it.

From the equation

1 mole of CH4 gave 1 mole of CO2

O.99 moles of CH4 will give x moles of CO2

$\frac{1}{1}$ = $\frac{x}{0.99}$

x = 0.99 moles of carbon dioxide

grams of CO2 = number of moles x atomic mass

                         = 0.99 x 44.01

                          = 43.56 grams of CO2 is produced.