Question

How many grams are in 1.25 moles of Potassium hydroxide, KOH?

1 point​

Answer 1

Answer:

There are 70 grams of KOH

Explanation:

First, we calculate the weight of 1 mol of KOH:

Weight 1 mol KOH: Weight K + Weight 0 + Weight H=  39g+ 1g+ 16g= 56 g/mol

1 mol-------56 g KOH

1,25 mol----x= (1,25 molx56 g KOH)/1 mol= 70 g KOH