The volume is increased to 4.52 L on decreasing the pressure to 93.3 kPa.
Explanation:
As per Boyle's law, the volume occupied by gas particles will be inversely proportional to the pressure experienced by those particles at constant temperature.
[tex]V=\frac{1}{P}[/tex]
So in the present problem, the volume of gas at pressure P₁ = 99.6 kPa is given as V₁ = 4.23 L. The temperature is kept constant at 24°C. Then, if the pressure is decreased to 93.3 kPa, then the volume is tend to increase due to Boyle's law.
So let us consider the new pressure be P₂ = 93.3 kPa and the new volume has to be found.
Then using Boyle's law, [tex]P_{1} V_{1} = P_{2} V_{2}[/tex]
Then, [tex]V_{2}=\frac{P_{1} V_{1} }{P_{2} }[/tex]
So, [tex]V_{2}=\frac{99.6*1000*4.23}{93.3*1000}=4.52 L[/tex]
Thus, the volume is increased to 4.52 L on decreasing the pressure to 93.3 kPa.