Answer:
[tex]20,475\ ways[/tex]
Step-by-step explanation:
we know that
Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter.
To calculate combinations, we will use the formula
[tex]C(n,r)=\frac{n!}{r!(n-r)!}[/tex]
where
n represents the total number of items
r represents the number of items being chosen at a time.
In this problem
[tex]n=28\\r=4[/tex]
substitute
[tex]C(28,4)=\frac{28!}{4!(28-4)!}\\\\C(28,4)=\frac{28!}{4!(24)!}[/tex]
simplify
[tex]C(28,4)=\frac{(28)(27)(26)(25)(24!)}{4!(24)!}\\\\C(28,4)=\frac{(28)(27)(26)(25)}{(4)(3)(2)(1)}\\\\C(28,4)=20,475\ ways[/tex]