Question

A ray of light traveling in water (n = 1.33) is incident at the flat surface of a block of glass (n = 1.60). If the incident ray in water makes an angle of 36.6° with the normal to the interface, what angle does the ray that is refracted into the glass make with the normal?

Answer 1

Answer:

θ₂ ≈ 29.7°

Explanation:

Given:

n₁ = 1.33, n₂= 1.60, θ₁ = 36.6°, θ₂ = ?

Solution:

According to snell's Law

n₁ sin θ₁ = n₂ sin θ₂

1.33 × sin (36.6°) = 1.60 × sin θ₂

⇒ Sin θ₂ = 0.496

θ₂ ≈ 29.7°